It suggests zero or more occurrence of whitespace people, followed by a comma then followed by zero or even more occurrence of whitespace people. Even so x.replaceAll("\s+", ""); will likely be much more economical way of trimming Areas (if string can have various contiguous spaces) because of doubtless much less https://mantra-bars-euphoria-bar87530.blogkoo.com/about-mantra-euphoria-gummie-50959657